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Polynomials

A factor is a place where the curve hits zero.

Here is f(x)=x3−2x2−5x+6f(x) = x^3 - 2x^2 - 5x + 6. Slide along it and watch the height: every time it drops to exactly zero, you've found a factor.

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The factor theorem

f(k)=0  ⟺  (x−k) is a factorf(k) = 0 \iff (x - k) \text{ is a factor}

Divide f(x)f(x) by (x−k)(x - k) and the remainder is exactly f(k)f(k). So wherever the curve crosses the axis, the division comes out clean.

Testing for factors

f(1)=1−2−5+6=0f(1) = 1 - 2 - 5 + 6 = 0, so (x−1)(x - 1) is a factor.

f(2)=8−8−10+6=−4f(2) = 8 - 8 - 10 + 6 = -4: dividing by (x−2)(x - 2) would leave remainder −4-4, so it isn't.

Factorising fully

Dividing by (x−1)(x - 1) leaves x2−x−6x^2 - x - 6 with no remainder — and that quadratic factorises too:

f(x)=(x−1)(x−3)(x+2)f(x) = (x - 1)(x - 3)(x + 2)

Sketching

Three factors, three roots: −2-2, 11 and 33, all clean crossings. f(0)=6f(0) = 6 gives the yy-intercept, and the x3x^3 term sends it from bottom-left to top-right.

Chapter 6

Find one root, and the rest follow.

The grid method, the remainder theorem, repeated roots, and twelve graded exam questions with full worked solutions are waiting.