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Indices & surds

An index is just counting.

a3a^3 means three aa's multiplied together — nothing more. Keep that picture of tiles in your head and every law of indices becomes obvious.

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Multiplying

am×an=am+na^m \times a^n = a^{m+n}

a3×a2a^3 \times a^2 is three tiles next to two: five tiles, a5a^5. Multiplying powers adds the indices, because all you're doing is counting tiles.

Dividing

am÷an=am−n,a−n=1ana^m \div a^n = a^{m-n}, \qquad a^{-n} = \frac{1}{a^n}

Dividing cancels tiles in pairs. a5÷a2a^5 \div a^2 leaves three on top. a2÷a5a^2 \div a^5 leaves three underneath: that's what a−3a^{-3} means. Cancel everything and you get a0=1a^0 = 1.

Fractional indices

a1n=ana^{\frac{1}{n}} = \sqrt[n]{a}

A square of area 25 has side 5, so 2512=525^{\frac{1}{2}} = 5: a power of a half is a square root. In general the bottom of the fraction is the root and the top is the power — 823=(83)2=48^{\frac{2}{3}} = (\sqrt[3]{8})^2 = 4.

Surds

ab=a b\sqrt{ab} = \sqrt{a}\,\sqrt{b}

Pull out the largest square: 75=53\sqrt{75} = 5\sqrt{3} and 27=33\sqrt{27} = 3\sqrt{3}. Now they're like terms — five lengths of 3\sqrt{3} and three more — so 75+27=83\sqrt{75} + \sqrt{27} = 8\sqrt{3}.

Rationalising

(a+b)(a−b)=a−b2(\sqrt{a} + b)(\sqrt{a} - b) = a - b^2

Multiply by the conjugate and the difference of two squares wipes the surd out of the denominator: 67+1=7−1\tfrac{6}{\sqrt{7} + 1} = \sqrt{7} - 1. Same number — both are 1.64575…1.64575\ldots — just with no surd underneath.

Chapter 1

Count the tiles. Pull out the squares.

All six index laws, negative and fractional powers, harder conjugates, and twelve graded exam questions with full worked solutions are waiting.